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115500545435273 is a prime number
BaseRepresentation
bin11010010000110000010000…
…111110110110011010001001
3120010221202002121012121022012
4122100300100332312122021
5110114330104112412043
61045352115034105305
733220432121341565
oct3220602076663211
9503852077177265
10115500545435273
11338905628947a9
1210b54942b7b235
134c5a8684b604b
14207438312c6a5
15d5467a8a7a18
hex690c10fb6689

115500545435273 has 2 divisors, whose sum is σ = 115500545435274. Its totient is φ = 115500545435272.

The previous prime is 115500545435251. The next prime is 115500545435291. The reversal of 115500545435273 is 372534545005511.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 113568409295104 + 1932136140169 = 10656848^2 + 1390013^2 .

It is a cyclic number.

It is not a de Polignac number, because 115500545435273 - 214 = 115500545418889 is a prime.

It is not a weakly prime, because it can be changed into another prime (115500545035273) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57750272717636 + 57750272717637.

It is an arithmetic number, because the mean of its divisors is an integer number (57750272717637).

Almost surely, 2115500545435273 is an apocalyptic number.

It is an amenable number.

115500545435273 is a deficient number, since it is larger than the sum of its proper divisors (1).

115500545435273 is an equidigital number, since it uses as much as digits as its factorization.

115500545435273 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6300000, while the sum is 50.

The spelling of 115500545435273 in words is "one hundred fifteen trillion, five hundred billion, five hundred forty-five million, four hundred thirty-five thousand, two hundred seventy-three".