Search a number
-
+
11550252200783 is a prime number
BaseRepresentation
bin1010100000010100000010…
…1011011111001101001111
31111220012012221020200121112
42220011000223133031033
53003214404030411113
640322040153522235
72301323005545002
oct250050053371517
944805187220545
1011550252200783
11375348628665a
12136662411337b
1365a251644b7a
142bd06c7b9539
151506add9d5a8
hexa8140adf34f

11550252200783 has 2 divisors, whose sum is σ = 11550252200784. Its totient is φ = 11550252200782.

The previous prime is 11550252200749. The next prime is 11550252200791. The reversal of 11550252200783 is 38700225205511.

It is a strong prime.

It is an emirp because it is prime and its reverse (38700225205511) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11550252200783 is a prime.

It is a Sophie Germain prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11550252200783.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11550252260783) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5775126100391 + 5775126100392.

It is an arithmetic number, because the mean of its divisors is an integer number (5775126100392).

Almost surely, 211550252200783 is an apocalyptic number.

11550252200783 is a deficient number, since it is larger than the sum of its proper divisors (1).

11550252200783 is an equidigital number, since it uses as much as digits as its factorization.

11550252200783 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 168000, while the sum is 41.

The spelling of 11550252200783 in words is "eleven trillion, five hundred fifty billion, two hundred fifty-two million, two hundred thousand, seven hundred eighty-three".