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115505120502253 is a prime number
BaseRepresentation
bin11010010000110100100001…
…101011010110000111101101
3120010222011220110000002100101
4122100310201223112013231
5110114413441322033003
61045354153025431101
733220653363641356
oct3220644153260755
9503864813002311
10115505120502253
11338924a0347299
1210b557bb19b491
134c5b1172b3781
1420746989b8d2d
15d5484737311d
hex690d21ad61ed

115505120502253 has 2 divisors, whose sum is σ = 115505120502254. Its totient is φ = 115505120502252.

The previous prime is 115505120502217. The next prime is 115505120502259. The reversal of 115505120502253 is 352205021505511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 115470111472804 + 35009029449 = 10745702^2 + 187107^2 .

It is a cyclic number.

It is not a de Polignac number, because 115505120502253 - 237 = 115367681548781 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (115505120502259) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57752560251126 + 57752560251127.

It is an arithmetic number, because the mean of its divisors is an integer number (57752560251127).

Almost surely, 2115505120502253 is an apocalyptic number.

It is an amenable number.

115505120502253 is a deficient number, since it is larger than the sum of its proper divisors (1).

115505120502253 is an equidigital number, since it uses as much as digits as its factorization.

115505120502253 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 75000, while the sum is 37.

The spelling of 115505120502253 in words is "one hundred fifteen trillion, five hundred five billion, one hundred twenty million, five hundred two thousand, two hundred fifty-three".