Base | Representation |
---|---|
bin | 10101100001000001… |
… | …11000101010111111 |
3 | 1002211000220010212022 |
4 | 22300200320222333 |
5 | 142124121022333 |
6 | 5150121230355 |
7 | 556152546446 |
oct | 126040705277 |
9 | 32730803768 |
10 | 11551345343 |
11 | 49984847aa |
12 | 22a46323bb |
13 | 11212192b5 |
14 | 7b81cdd5d |
15 | 47919ac98 |
hex | 2b0838abf |
11551345343 has 2 divisors, whose sum is σ = 11551345344. Its totient is φ = 11551345342.
The previous prime is 11551345339. The next prime is 11551345349. The reversal of 11551345343 is 34354315511.
11551345343 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11551345343 - 22 = 11551345339 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11551345349) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5775672671 + 5775672672.
It is an arithmetic number, because the mean of its divisors is an integer number (5775672672).
Almost surely, 211551345343 is an apocalyptic number.
11551345343 is a deficient number, since it is larger than the sum of its proper divisors (1).
11551345343 is an equidigital number, since it uses as much as digits as its factorization.
11551345343 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 54000, while the sum is 35.
The spelling of 11551345343 in words is "eleven billion, five hundred fifty-one million, three hundred forty-five thousand, three hundred forty-three".
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