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11552024401153 is a prime number
BaseRepresentation
bin1010100000011010101001…
…0011111001010100000001
31111220100210102221210111021
42220012222103321110001
53003232021221314103
640322532102145441
72301414635156635
oct250065223712401
944810712853437
1011552024401153
113754205682a65
121366a39722281
1365a474850642
142bd199cd6dc5
15150764764bbd
hexa81aa4f9501

11552024401153 has 2 divisors, whose sum is σ = 11552024401154. Its totient is φ = 11552024401152.

The previous prime is 11552024401037. The next prime is 11552024401189. The reversal of 11552024401153 is 35110442025511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11433710416129 + 118313985024 = 3381377^2 + 343968^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11552024401153 is a prime.

It is not a weakly prime, because it can be changed into another prime (11552024404153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5776012200576 + 5776012200577.

It is an arithmetic number, because the mean of its divisors is an integer number (5776012200577).

Almost surely, 211552024401153 is an apocalyptic number.

It is an amenable number.

11552024401153 is a deficient number, since it is larger than the sum of its proper divisors (1).

11552024401153 is an equidigital number, since it uses as much as digits as its factorization.

11552024401153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24000, while the sum is 34.

Adding to 11552024401153 its reverse (35110442025511), we get a palindrome (46662466426664).

The spelling of 11552024401153 in words is "eleven trillion, five hundred fifty-two billion, twenty-four million, four hundred one thousand, one hundred fifty-three".