Base | Representation |
---|---|
bin | 1010100000011011001010… |
… | …1000110110111001010011 |
3 | 1111220101011011211221111021 |
4 | 2220012302220312321103 |
5 | 3003232313003122003 |
6 | 40322554012500311 |
7 | 2301421252543012 |
oct | 250066250667123 |
9 | 44811134757437 |
10 | 11552164114003 |
11 | 3754277529327 |
12 | 1366a7847a697 |
13 | 65a49778a076 |
14 | 2bd1b06a4a79 |
15 | 150771b612bd |
hex | a81b2a36e53 |
11552164114003 has 2 divisors, whose sum is σ = 11552164114004. Its totient is φ = 11552164114002.
The previous prime is 11552164113991. The next prime is 11552164114009. The reversal of 11552164114003 is 30041146125511.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11552164114003 - 233 = 11543574179411 is a prime.
It is a super-3 number, since 3×115521641140033 (a number of 40 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 11552164114003.
It is not a weakly prime, because it can be changed into another prime (11552164114009) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5776082057001 + 5776082057002.
It is an arithmetic number, because the mean of its divisors is an integer number (5776082057002).
Almost surely, 211552164114003 is an apocalyptic number.
11552164114003 is a deficient number, since it is larger than the sum of its proper divisors (1).
11552164114003 is an equidigital number, since it uses as much as digits as its factorization.
11552164114003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 14400, while the sum is 34.
The spelling of 11552164114003 in words is "eleven trillion, five hundred fifty-two billion, one hundred sixty-four million, one hundred fourteen thousand, three".
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