Base | Representation |
---|---|
bin | 100010011011011… |
… | …1100011100011001 |
3 | 2222111210222121201 |
4 | 1010312330130121 |
5 | 4331221112131 |
6 | 310345034201 |
7 | 40425332404 |
oct | 10466743431 |
9 | 2874728551 |
10 | 1155254041 |
11 | 543124507 |
12 | 282a85961 |
13 | 155458696 |
14 | ad602d3b |
15 | 6b64c761 |
hex | 44dbc719 |
1155254041 has 2 divisors, whose sum is σ = 1155254042. Its totient is φ = 1155254040.
The previous prime is 1155254027. The next prime is 1155254099. The reversal of 1155254041 is 1404525511.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1140075225 + 15178816 = 33765^2 + 3896^2 .
It is an emirp because it is prime and its reverse (1404525511) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1155254041 - 29 = 1155253529 is a prime.
It is a super-2 number, since 2×11552540412 = 2669223798493659362, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1155254021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 577627020 + 577627021.
It is an arithmetic number, because the mean of its divisors is an integer number (577627021).
Almost surely, 21155254041 is an apocalyptic number.
It is an amenable number.
1155254041 is a deficient number, since it is larger than the sum of its proper divisors (1).
1155254041 is an equidigital number, since it uses as much as digits as its factorization.
1155254041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4000, while the sum is 28.
The square root of 1155254041 is about 33989.0282444203. The cubic root of 1155254041 is about 1049.2826668128.
Adding to 1155254041 its reverse (1404525511), we get a palindrome (2559779552).
The spelling of 1155254041 in words is "one billion, one hundred fifty-five million, two hundred fifty-four thousand, forty-one".
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