Base | Representation |
---|---|
bin | 1010100000011110100001… |
… | …0101100101001100000111 |
3 | 1111220110110222002020110111 |
4 | 2220013220111211030013 |
5 | 3003241134121433112 |
6 | 40323223234333451 |
7 | 2301452502316315 |
oct | 250075025451407 |
9 | 44813428066414 |
10 | 11553065030407 |
11 | 375469a02713a |
12 | 136708a12a287 |
13 | 65a5ac3148b4 |
14 | 2bd2581bd0b5 |
15 | 1507c5cbe5a7 |
hex | a81e8565307 |
11553065030407 has 2 divisors, whose sum is σ = 11553065030408. Its totient is φ = 11553065030406.
The previous prime is 11553065030347. The next prime is 11553065030413. The reversal of 11553065030407 is 70403056035511.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11553065030407 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11553065030407.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11553065930407) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5776532515203 + 5776532515204.
It is an arithmetic number, because the mean of its divisors is an integer number (5776532515204).
Almost surely, 211553065030407 is an apocalyptic number.
11553065030407 is a deficient number, since it is larger than the sum of its proper divisors (1).
11553065030407 is an equidigital number, since it uses as much as digits as its factorization.
11553065030407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 189000, while the sum is 40.
The spelling of 11553065030407 in words is "eleven trillion, five hundred fifty-three billion, sixty-five million, thirty thousand, four hundred seven".
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