Base | Representation |
---|---|
bin | 11010010001001110110111… |
… | …011001011101110100001001 |
3 | 120011001212220110000021000102 |
4 | 122101032313121131310021 |
5 | 110120344401430420403 |
6 | 1045415151240415145 |
7 | 33223004260263533 |
oct | 3221166731356411 |
9 | 504055813007012 |
10 | 115533402201353 |
11 | 338a3493658434 |
12 | 10b5b1927774b5 |
13 | 4c609a3692376 |
14 | 2075bbcb36853 |
15 | d554501d0b88 |
hex | 6913b765dd09 |
115533402201353 has 2 divisors, whose sum is σ = 115533402201354. Its totient is φ = 115533402201352.
The previous prime is 115533402201341. The next prime is 115533402201467. The reversal of 115533402201353 is 353102204335511.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 107434323692809 + 8099078508544 = 10365053^2 + 2845888^2 .
It is a cyclic number.
It is not a de Polignac number, because 115533402201353 - 24 = 115533402201337 is a prime.
It is not a weakly prime, because it can be changed into another prime (115533402201253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57766701100676 + 57766701100677.
It is an arithmetic number, because the mean of its divisors is an integer number (57766701100677).
Almost surely, 2115533402201353 is an apocalyptic number.
It is an amenable number.
115533402201353 is a deficient number, since it is larger than the sum of its proper divisors (1).
115533402201353 is an equidigital number, since it uses as much as digits as its factorization.
115533402201353 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 162000, while the sum is 38.
Adding to 115533402201353 its reverse (353102204335511), we get a palindrome (468635606536864).
The spelling of 115533402201353 in words is "one hundred fifteen trillion, five hundred thirty-three billion, four hundred two million, two hundred one thousand, three hundred fifty-three".
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