115540133 has 2 divisors, whose sum is σ = 115540134. Its totient is φ = 115540132.

The previous prime is 115540123. The next prime is 115540141. The reversal of 115540133 is 331045511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 89151364 + 26388769 = 9442^2 + 5137^2 .

It is an emirp because it is prime and its reverse (331045511) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-115540133 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 115540099 and 115540108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (115540123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57770066 + 57770067.

It is an arithmetic number, because the mean of its divisors is an integer number (57770067).

Almost surely, 2^115540133 is an apocalyptic number.

It is an amenable number.

115540133 is a deficient number, since it is larger than the sum of its proper divisors (1).

115540133 is an equidigital number, since it uses as much as digits as its factorization.

115540133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 900, while the sum is 23.

The square root of 115540133 is about 10748.9596240753. The cubic root of 115540133 is about 487.0545681904.

Adding to 115540133 its reverse (331045511), we get a palindrome (446585644).

The spelling of 115540133 in words is "one hundred fifteen million, five hundred forty thousand, one hundred thirty-three".