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11554154254001 is a prime number
BaseRepresentation
bin1010100000100010100101…
…0000101000111010110001
31111220120021212122112100002
42220020221100220322301
53003300401442112001
640323523304235345
72301521466500312
oct250105120507261
944816255575302
1011554154254001
1137550a8950a27
121367332a6bb55
1365a723b914b8
142bd31cb14609
1515083b72746b
hexa8229428eb1

11554154254001 has 2 divisors, whose sum is σ = 11554154254002. Its totient is φ = 11554154254000.

The previous prime is 11554154253923. The next prime is 11554154254033. The reversal of 11554154254001 is 10045245145511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10843842414001 + 710311840000 = 3292999^2 + 842800^2 .

It is a cyclic number.

It is not a de Polignac number, because 11554154254001 - 226 = 11554087145137 is a prime.

It is not a weakly prime, because it can be changed into another prime (11554154254051) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5777077127000 + 5777077127001.

It is an arithmetic number, because the mean of its divisors is an integer number (5777077127001).

Almost surely, 211554154254001 is an apocalyptic number.

It is an amenable number.

11554154254001 is a deficient number, since it is larger than the sum of its proper divisors (1).

11554154254001 is an equidigital number, since it uses as much as digits as its factorization.

11554154254001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 80000, while the sum is 38.

Adding to 11554154254001 its reverse (10045245145511), we get a palindrome (21599399399512).

The spelling of 11554154254001 in words is "eleven trillion, five hundred fifty-four billion, one hundred fifty-four million, two hundred fifty-four thousand, one".