Base | Representation |
---|---|
bin | 11010010001011111010010… |
… | …110011110011110101111111 |
3 | 120011010120102210022220122111 |
4 | 122101133102303303311333 |
5 | 110121142013220230333 |
6 | 1045431225453554451 |
7 | 33224200352622322 |
oct | 3221372263636577 |
9 | 504116383286574 |
10 | 115551041961343 |
11 | 338aaa1586117a |
12 | 10b626961a5a27 |
13 | 4c62555092881 |
14 | 20769b378c7b9 |
15 | d55b33b2b4cd |
hex | 6917d2cf3d7f |
115551041961343 has 2 divisors, whose sum is σ = 115551041961344. Its totient is φ = 115551041961342.
The previous prime is 115551041961337. The next prime is 115551041961359. The reversal of 115551041961343 is 343169140155511.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-115551041961343 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (115551041961323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57775520980671 + 57775520980672.
It is an arithmetic number, because the mean of its divisors is an integer number (57775520980672).
Almost surely, 2115551041961343 is an apocalyptic number.
115551041961343 is a deficient number, since it is larger than the sum of its proper divisors (1).
115551041961343 is an equidigital number, since it uses as much as digits as its factorization.
115551041961343 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972000, while the sum is 49.
The spelling of 115551041961343 in words is "one hundred fifteen trillion, five hundred fifty-one billion, forty-one million, nine hundred sixty-one thousand, three hundred forty-three".
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