Base | Representation |
---|---|
bin | 10101100001011110… |
… | …10000111100110001 |
3 | 1002211021222122120212 |
4 | 22300233100330301 |
5 | 142131102133201 |
6 | 5150334113505 |
7 | 556226566226 |
oct | 126057207461 |
9 | 32737878525 |
10 | 11555114801 |
11 | 499a61985a |
12 | 22a594b895 |
13 | 1121c38c49 |
14 | 7b88d194d |
15 | 479692abb |
hex | 2b0bd0f31 |
11555114801 has 2 divisors, whose sum is σ = 11555114802. Its totient is φ = 11555114800.
The previous prime is 11555114797. The next prime is 11555114807. The reversal of 11555114801 is 10841155511.
11555114801 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7093008400 + 4462106401 = 84220^2 + 66799^2 .
It is a cyclic number.
It is not a de Polignac number, because 11555114801 - 22 = 11555114797 is a prime.
It is not a weakly prime, because it can be changed into another prime (11555114807) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5777557400 + 5777557401.
It is an arithmetic number, because the mean of its divisors is an integer number (5777557401).
Almost surely, 211555114801 is an apocalyptic number.
It is an amenable number.
11555114801 is a deficient number, since it is larger than the sum of its proper divisors (1).
11555114801 is an equidigital number, since it uses as much as digits as its factorization.
11555114801 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4000, while the sum is 32.
The spelling of 11555114801 in words is "eleven billion, five hundred fifty-five million, one hundred fourteen thousand, eight hundred one".
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