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115551433 is a prime number
BaseRepresentation
bin1101110001100…
…10110011001001
322001102121202201
412320302303021
5214040121213
615244400201
72602112434
oct670626311
9261377681
10115551433
115a253558
1232846061
131ac2a13a
14114bc81b
15a2276dd
hex6e32cc9

115551433 has 2 divisors, whose sum is σ = 115551434. Its totient is φ = 115551432.

The previous prime is 115551421. The next prime is 115551461. The reversal of 115551433 is 334155511.

It is an a-pointer prime, because the next prime (115551461) can be obtained adding 115551433 to its sum of digits (28).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 102677689 + 12873744 = 10133^2 + 3588^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-115551433 is a prime.

It is not a weakly prime, because it can be changed into another prime (115551413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57775716 + 57775717.

It is an arithmetic number, because the mean of its divisors is an integer number (57775717).

Almost surely, 2115551433 is an apocalyptic number.

It is an amenable number.

115551433 is a deficient number, since it is larger than the sum of its proper divisors (1).

115551433 is an equidigital number, since it uses as much as digits as its factorization.

115551433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 4500, while the sum is 28.

The square root of 115551433 is about 10749.4852434896. The cubic root of 115551433 is about 487.0704458976.

The spelling of 115551433 in words is "one hundred fifteen million, five hundred fifty-one thousand, four hundred thirty-three".