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11560647413213 is a prime number
BaseRepresentation
bin1010100000111010110001…
…0010000100110111011101
31111221012001101200012021022
42220032230102010313131
53003402201214210323
640330515455213525
72302141422441533
oct250165422046735
944835041605238
1011560647413213
113757930096608
1213686455172a5
1365b21a188742
142bd777218153
15150abb7c64c8
hexa83ac484ddd

11560647413213 has 2 divisors, whose sum is σ = 11560647413214. Its totient is φ = 11560647413212.

The previous prime is 11560647413201. The next prime is 11560647413267. The reversal of 11560647413213 is 31231474606511.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11522677773049 + 37969640164 = 3394507^2 + 194858^2 .

It is a cyclic number.

It is not a de Polignac number, because 11560647413213 - 212 = 11560647409117 is a prime.

It is a super-2 number, since 2×115606474132132 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11560647413713) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5780323706606 + 5780323706607.

It is an arithmetic number, because the mean of its divisors is an integer number (5780323706607).

Almost surely, 211560647413213 is an apocalyptic number.

It is an amenable number.

11560647413213 is a deficient number, since it is larger than the sum of its proper divisors (1).

11560647413213 is an equidigital number, since it uses as much as digits as its factorization.

11560647413213 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 362880, while the sum is 44.

The spelling of 11560647413213 in words is "eleven trillion, five hundred sixty billion, six hundred forty-seven million, four hundred thirteen thousand, two hundred thirteen".