Base | Representation |
---|---|
bin | 10101100010010000… |
… | …01000010101101011 |
3 | 1002211202020211001111 |
4 | 22301020020111223 |
5 | 142134234230011 |
6 | 5151125531151 |
7 | 556336155136 |
oct | 126110102553 |
9 | 32752224044 |
10 | 11561633131 |
11 | 49a3271104 |
12 | 22a7b73ab7 |
13 | 11233abb49 |
14 | 7b970b21d |
15 | 47a02e121 |
hex | 2b120856b |
11561633131 has 2 divisors, whose sum is σ = 11561633132. Its totient is φ = 11561633130.
The previous prime is 11561633101. The next prime is 11561633137. The reversal of 11561633131 is 13133616511.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11561633131 - 213 = 11561624939 is a prime.
It is a super-2 number, since 2×115616331312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11561633093 and 11561633102.
It is not a weakly prime, because it can be changed into another prime (11561633137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5780816565 + 5780816566.
It is an arithmetic number, because the mean of its divisors is an integer number (5780816566).
Almost surely, 211561633131 is an apocalyptic number.
11561633131 is a deficient number, since it is larger than the sum of its proper divisors (1).
11561633131 is an equidigital number, since it uses as much as digits as its factorization.
11561633131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 4860, while the sum is 31.
The spelling of 11561633131 in words is "eleven billion, five hundred sixty-one million, six hundred thirty-three thousand, one hundred thirty-one".
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