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11563200212344 = 2311131400002413
BaseRepresentation
bin1010100001000100010001…
…1100001110110101111000
31111221102122022012211100021
42220101010130032311320
53003422413223243334
640332021050420224
72302261611043564
oct250210434166570
944842568184307
1011563200212344
113758a20082360
121369038431674
1365b536013381
142bd93a2906a4
15150bba9813b4
hexa844470ed78

11563200212344 has 16 divisors (see below), whose sum is σ = 23652000434520. Its totient is φ = 5256000096480.

The previous prime is 11563200212329. The next prime is 11563200212363. The reversal of 11563200212344 is 44321200236511.

It is a super-3 number, since 3×115632002123443 (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 65700001119 + ... + 65700001294.

Almost surely, 211563200212344 is an apocalyptic number.

It is an amenable number.

11563200212344 is an abundant number, since it is smaller than the sum of its proper divisors (12088800222176).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11563200212344 is a wasteful number, since it uses less digits than its factorization.

11563200212344 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 131400002430 (or 131400002426 counting only the distinct ones).

The product of its (nonzero) digits is 34560, while the sum is 34.

Adding to 11563200212344 its reverse (44321200236511), we get a palindrome (55884400448855).

The spelling of 11563200212344 in words is "eleven trillion, five hundred sixty-three billion, two hundred million, two hundred twelve thousand, three hundred forty-four".

Divisors: 1 2 4 8 11 22 44 88 131400002413 262800004826 525600009652 1051200019304 1445400026543 2890800053086 5781600106172 11563200212344