Base | Representation |
---|---|
bin | 10000110101000000110… |
… | …010111111111001110101 |
3 | 11002112221211022010021011 |
4 | 100311000302333321311 |
5 | 122421333412012042 |
6 | 2243131431152221 |
7 | 146356331656015 |
oct | 20650062777165 |
9 | 4075854263234 |
10 | 1156433313397 |
11 | 40649350367a |
12 | 16815b215671 |
13 | 8508861a4cb |
14 | 3dd8639dc45 |
15 | 20135022a17 |
hex | 10d40cbfe75 |
1156433313397 has 2 divisors, whose sum is σ = 1156433313398. Its totient is φ = 1156433313396.
The previous prime is 1156433313377. The next prime is 1156433313491. The reversal of 1156433313397 is 7933133346511.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 640393660516 + 516039652881 = 800246^2 + 718359^2 .
It is a cyclic number.
It is not a de Polignac number, because 1156433313397 - 227 = 1156299095669 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1156433313397.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1156433313377) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 578216656698 + 578216656699.
It is an arithmetic number, because the mean of its divisors is an integer number (578216656699).
Almost surely, 21156433313397 is an apocalyptic number.
It is an amenable number.
1156433313397 is a deficient number, since it is larger than the sum of its proper divisors (1).
1156433313397 is an equidigital number, since it uses as much as digits as its factorization.
1156433313397 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1837080, while the sum is 49.
The spelling of 1156433313397 in words is "one trillion, one hundred fifty-six billion, four hundred thirty-three million, three hundred thirteen thousand, three hundred ninety-seven".
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