Base | Representation |
---|---|
bin | 110101110111010101… |
… | …1000101000110101001 |
3 | 102001120110221120210012 |
4 | 1223232223011012221 |
5 | 3343344343421301 |
6 | 125050054501305 |
7 | 11233331564063 |
oct | 1535653050651 |
9 | 361513846705 |
10 | 115673420201 |
11 | 450696a2739 |
12 | 1a502964835 |
13 | aba5a1c891 |
14 | 58548a0733 |
15 | 3020220ebb |
hex | 1aeeac51a9 |
115673420201 has 2 divisors, whose sum is σ = 115673420202. Its totient is φ = 115673420200.
The previous prime is 115673420179. The next prime is 115673420221. The reversal of 115673420201 is 102024376511.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 60589330201 + 55084090000 = 246149^2 + 234700^2 .
It is a cyclic number.
It is not a de Polignac number, because 115673420201 - 214 = 115673403817 is a prime.
It is a super-2 number, since 2×1156734202012 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (115673420221) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57836710100 + 57836710101.
It is an arithmetic number, because the mean of its divisors is an integer number (57836710101).
Almost surely, 2115673420201 is an apocalyptic number.
It is an amenable number.
115673420201 is a deficient number, since it is larger than the sum of its proper divisors (1).
115673420201 is an equidigital number, since it uses as much as digits as its factorization.
115673420201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10080, while the sum is 32.
Adding to 115673420201 its reverse (102024376511), we get a palindrome (217697796712).
The spelling of 115673420201 in words is "one hundred fifteen billion, six hundred seventy-three million, four hundred twenty thousand, two hundred one".
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