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11580103 is a prime number
BaseRepresentation
bin101100001011…
…001011000111
3210210022220201
4230023023013
510431030403
61052111331
7200300143
oct54131307
923708821
1011580103
11659a337
123a65547
132525b42
141776223
15103b21d
hexb0b2c7

11580103 has 2 divisors, whose sum is σ = 11580104. Its totient is φ = 11580102.

The previous prime is 11580091. The next prime is 11580113. The reversal of 11580103 is 30108511.

11580103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11580103 - 25 = 11580071 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11580113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5790051 + 5790052.

It is an arithmetic number, because the mean of its divisors is an integer number (5790052).

Almost surely, 211580103 is an apocalyptic number.

11580103 is a deficient number, since it is larger than the sum of its proper divisors (1).

11580103 is an equidigital number, since it uses as much as digits as its factorization.

11580103 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 120, while the sum is 19.

The square root of 11580103 is about 3402.9550393739. The cubic root of 11580103 is about 226.2407372865.

Adding to 11580103 its reverse (30108511), we get a palindrome (41688614).

It can be divided in two parts, 11580 and 103, that multiplied together give a triangular number (1192740 = T1544).

The spelling of 11580103 in words is "eleven million, five hundred eighty thousand, one hundred three".