11583141340333 has 2 divisors, whose sum is σ = 11583141340334. Its totient is φ = 11583141340332.

The previous prime is 11583141340307. The next prime is 11583141340339. The reversal of 11583141340333 is 33304314138511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11552473625449 + 30667714884 = 3398893^2 + 175122^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11583141340333 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11583141340339) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5791570670166 + 5791570670167.

It is an arithmetic number, because the mean of its divisors is an integer number (5791570670167).

Almost surely, 2^{11583141340333} is an apocalyptic number.

It is an amenable number.

11583141340333 is a deficient number, since it is larger than the sum of its proper divisors (1).

11583141340333 is an equidigital number, since it uses as much as digits as its factorization.

11583141340333 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 155520, while the sum is 40.

Adding to 11583141340333 its reverse (33304314138511), we get a palindrome (44887455478844).

The spelling of 11583141340333 in words is "eleven trillion, five hundred eighty-three billion, one hundred forty-one million, three hundred forty thousand, three hundred thirty-three".