Base | Representation |
---|---|
bin | 11010010111100100111101… |
… | …011110000011101110000111 |
3 | 120012121120101220011112212221 |
4 | 122113210331132003232013 |
5 | 110200020404432432111 |
6 | 1050351343213353211 |
7 | 33266341625112361 |
oct | 3227447536035607 |
9 | 505546356145787 |
10 | 115969443249031 |
11 | 33a51401440349 |
12 | 1100b7a3a98807 |
13 | 4c92b43b03c08 |
14 | 208cd45799d31 |
15 | d61970c48371 |
hex | 69793d783b87 |
115969443249031 has 2 divisors, whose sum is σ = 115969443249032. Its totient is φ = 115969443249030.
The previous prime is 115969443249001. The next prime is 115969443249041. The reversal of 115969443249031 is 130942344969511.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 115969443249031 - 217 = 115969443117959 is a prime.
It is a super-2 number, since 2×1159694432490312 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (115969443249001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57984721624515 + 57984721624516.
It is an arithmetic number, because the mean of its divisors is an integer number (57984721624516).
Almost surely, 2115969443249031 is an apocalyptic number.
115969443249031 is a deficient number, since it is larger than the sum of its proper divisors (1).
115969443249031 is an equidigital number, since it uses as much as digits as its factorization.
115969443249031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 25194240, while the sum is 61.
The spelling of 115969443249031 in words is "one hundred fifteen trillion, nine hundred sixty-nine billion, four hundred forty-three million, two hundred forty-nine thousand, thirty-one".
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