Base | Representation |
---|---|
bin | 11010011000000100010100… |
… | …011111101010101100100010 |
3 | 120012201210022120112100000000 |
4 | 122120010110133222230202 |
5 | 110201043340034341310 |
6 | 1050415032351440430 |
7 | 33301643225643531 |
oct | 3230042437525442 |
9 | 505653276470000 |
10 | 116003115543330 |
11 | 33a64710590444 |
12 | 11016220826116 |
13 | 4c9607bc3c002 |
14 | 209081b812318 |
15 | d62791e644c0 |
hex | 6981147eab22 |
116003115543330 has 144 divisors (see below), whose sum is σ = 313815237712704. Its totient is φ = 30872656029600.
The previous prime is 116003115543319. The next prime is 116003115543373. The reversal of 116003115543330 is 33345511300611.
116003115543330 is a `hidden beast` number, since 1 + 1 + 6 + 0 + 0 + 311 + 5 + 5 + 4 + 3 + 330 = 666.
It is a super-2 number, since 2×1160031155433302 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 31244305 + ... + 34759355.
It is an arithmetic number, because the mean of its divisors is an integer number (2179272484116).
Almost surely, 2116003115543330 is an apocalyptic number.
116003115543330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is a practical number, because each smaller number is the sum of distinct divisors of 116003115543330, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (156907618856352).
116003115543330 is an abundant number, since it is smaller than the sum of its proper divisors (197812122169374).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
116003115543330 is an frugal number, since it uses more digits than its factorization.
116003115543330 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3515585 (or 3515564 counting only the distinct ones).
The product of its (nonzero) digits is 48600, while the sum is 36.
Adding to 116003115543330 its reverse (33345511300611), we get a palindrome (149348626843941).
The spelling of 116003115543330 in words is "one hundred sixteen trillion, three billion, one hundred fifteen million, five hundred forty-three thousand, three hundred thirty".
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