11600334488051 has 2 divisors, whose sum is σ = 11600334488052. Its totient is φ = 11600334488050.

The previous prime is 11600334488021. The next prime is 11600334488053. The reversal of 11600334488051 is 15088443300611.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11600334488051 is a prime.

Together with 11600334488053, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 11600334487993 and 11600334488011.

It is not a weakly prime, because it can be changed into another prime (11600334488053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5800167244025 + 5800167244026.

It is an arithmetic number, because the mean of its divisors is an integer number (5800167244026).

Almost surely, 2^{11600334488051} is an apocalyptic number.

11600334488051 is a deficient number, since it is larger than the sum of its proper divisors (1).

11600334488051 is an equidigital number, since it uses as much as digits as its factorization.

11600334488051 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 276480, while the sum is 44.

Adding to 11600334488051 its reverse (15088443300611), we get a palindrome (26688777788662).

The spelling of 11600334488051 in words is "eleven trillion, six hundred billion, three hundred thirty-four million, four hundred eighty-eight thousand, fifty-one".