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11600974670713 is a prime number
BaseRepresentation
bin1010100011010000111111…
…1110010110101101111001
31112002001010212112010122221
42220310033332112231321
53010032244003430323
640401225244244041
72305066652456041
oct250641776265571
945061125463587
1011600974670713
113772a44845a9a
12137441ab40621
13661c75c9069c
142c16c1052721
15151b7bda355d
hexa8d0ff96b79

11600974670713 has 2 divisors, whose sum is σ = 11600974670714. Its totient is φ = 11600974670712.

The previous prime is 11600974670683. The next prime is 11600974670743. The reversal of 11600974670713 is 31707647900611.

It is a balanced prime because it is at equal distance from previous prime (11600974670683) and next prime (11600974670743).

It can be written as a sum of positive squares in only one way, i.e., 11549856626064 + 51118044649 = 3398508^2 + 226093^2 .

It is an emirp because it is prime and its reverse (31707647900611) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11600974670713 - 217 = 11600974539641 is a prime.

It is a super-2 number, since 2×116009746707132 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11600974670743) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5800487335356 + 5800487335357.

It is an arithmetic number, because the mean of its divisors is an integer number (5800487335357).

Almost surely, 211600974670713 is an apocalyptic number.

It is an amenable number.

11600974670713 is a deficient number, since it is larger than the sum of its proper divisors (1).

11600974670713 is an equidigital number, since it uses as much as digits as its factorization.

11600974670713 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1333584, while the sum is 52.

The spelling of 11600974670713 in words is "eleven trillion, six hundred billion, nine hundred seventy-four million, six hundred seventy thousand, seven hundred thirteen".