Base | Representation |
---|---|
bin | 10000111000101000011… |
… | …011010111001010111101 |
3 | 11002220222122201100220222 |
4 | 100320220123113022331 |
5 | 123002313233300412 |
6 | 2245013212151125 |
7 | 146554540302002 |
oct | 20705033271275 |
9 | 4086878640828 |
10 | 1160319431357 |
11 | 4080a8084609 |
12 | 168a647684a5 |
13 | 855577778a8 |
14 | 4023454b8a9 |
15 | 202b12a0072 |
hex | 10e286d72bd |
1160319431357 has 2 divisors, whose sum is σ = 1160319431358. Its totient is φ = 1160319431356.
The previous prime is 1160319431311. The next prime is 1160319431377. The reversal of 1160319431357 is 7531349130611.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1159571463556 + 747967801 = 1076834^2 + 27349^2 .
It is a cyclic number.
It is not a de Polignac number, because 1160319431357 - 232 = 1156024464061 is a prime.
It is a super-2 number, since 2×11603194313572 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1160319431377) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 580159715678 + 580159715679.
It is an arithmetic number, because the mean of its divisors is an integer number (580159715679).
Almost surely, 21160319431357 is an apocalyptic number.
It is an amenable number.
1160319431357 is a deficient number, since it is larger than the sum of its proper divisors (1).
1160319431357 is an equidigital number, since it uses as much as digits as its factorization.
1160319431357 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 204120, while the sum is 44.
The spelling of 1160319431357 in words is "one trillion, one hundred sixty billion, three hundred nineteen million, four hundred thirty-one thousand, three hundred fifty-seven".
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