Base | Representation |
---|---|
bin | 110110000100101110… |
… | …0101110111000111111 |
3 | 102002201210020112000211 |
4 | 1230021130232320333 |
5 | 3400304344102111 |
6 | 125202423133251 |
7 | 11250425121412 |
oct | 1541134567077 |
9 | 362653215024 |
10 | 116122644031 |
11 | 4527a2291a9 |
12 | 1a6092a4227 |
13 | ac47b071b4 |
14 | 58983d9b79 |
15 | 30498a9521 |
hex | 1b0972ee3f |
116122644031 has 2 divisors, whose sum is σ = 116122644032. Its totient is φ = 116122644030.
The previous prime is 116122644019. The next prime is 116122644037. The reversal of 116122644031 is 130446221611.
It is a strong prime.
It is an emirp because it is prime and its reverse (130446221611) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 116122644031 - 29 = 116122643519 is a prime.
It is a super-2 number, since 2×1161226440312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 116122643984 and 116122644002.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (116122644037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 58061322015 + 58061322016.
It is an arithmetic number, because the mean of its divisors is an integer number (58061322016).
Almost surely, 2116122644031 is an apocalyptic number.
116122644031 is a deficient number, since it is larger than the sum of its proper divisors (1).
116122644031 is an equidigital number, since it uses as much as digits as its factorization.
116122644031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 31.
Adding to 116122644031 its reverse (130446221611), we get a palindrome (246568865642).
The spelling of 116122644031 in words is "one hundred sixteen billion, one hundred twenty-two million, six hundred forty-four thousand, thirty-one".
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