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11612571133 is a prime number
BaseRepresentation
bin10101101000010100…
…11100010111111101
31002222022002201212011
422310022130113331
5142240304234013
65200145411221
7560525140342
oct126412342775
932868081764
1011612571133
114a19aa2629
122301039b11
131130b05187
147c23aa7c9
1547e741c3d
hex2b429c5fd

11612571133 has 2 divisors, whose sum is σ = 11612571134. Its totient is φ = 11612571132.

The previous prime is 11612571079. The next prime is 11612571149. The reversal of 11612571133 is 33117521611.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6272323204 + 5340247929 = 79198^2 + 73077^2 .

It is an emirp because it is prime and its reverse (33117521611) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11612571133 - 217 = 11612440061 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11612571095 and 11612571104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11612571193) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5806285566 + 5806285567.

It is an arithmetic number, because the mean of its divisors is an integer number (5806285567).

Almost surely, 211612571133 is an apocalyptic number.

It is an amenable number.

11612571133 is a deficient number, since it is larger than the sum of its proper divisors (1).

11612571133 is an equidigital number, since it uses as much as digits as its factorization.

11612571133 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 3780, while the sum is 31.

The spelling of 11612571133 in words is "eleven billion, six hundred twelve million, five hundred seventy-one thousand, one hundred thirty-three".