Base | Representation |
---|---|
bin | 10101101000011000… |
… | …00111110100110101 |
3 | 1002222022221002120220 |
4 | 22310030013310311 |
5 | 142240412330003 |
6 | 5200203044553 |
7 | 560531652444 |
oct | 126414076465 |
9 | 32868832526 |
10 | 11613011253 |
11 | 4a1a273268 |
12 | 2301210759 |
13 | 1130c2a5bc |
14 | 7c2482d5b |
15 | 47e7cc353 |
hex | 2b4307d35 |
11613011253 has 32 divisors (see below), whose sum is σ = 16873853184. Its totient is φ = 7074542592.
The previous prime is 11613011251. The next prime is 11613011281. The reversal of 11613011253 is 35211031611.
11613011253 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 11613011253 - 21 = 11613011251 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11613011251) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 912651 + ... + 925287.
It is an arithmetic number, because the mean of its divisors is an integer number (527307912).
Almost surely, 211613011253 is an apocalyptic number.
It is an amenable number.
11613011253 is a deficient number, since it is larger than the sum of its proper divisors (5260841931).
11613011253 is a wasteful number, since it uses less digits than its factorization.
11613011253 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13181.
The product of its (nonzero) digits is 540, while the sum is 24.
Adding to 11613011253 its reverse (35211031611), we get a palindrome (46824042864).
The spelling of 11613011253 in words is "eleven billion, six hundred thirteen million, eleven thousand, two hundred fifty-three".
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