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116130513865183 is a prime number
BaseRepresentation
bin11010011001111010111110…
…000001101100100111011111
3120020011222011011221122010221
4122121322332001230213133
5110210140243022141213
61050553342131542211
733314103251550436
oct3231727601544737
9506158134848127
10116130513865183
1134003746619244
1211036a5615a967
134ca50a2b03acc
142096a6556011d
15d65c4b6b538d
hex699ebe06c9df

116130513865183 has 2 divisors, whose sum is σ = 116130513865184. Its totient is φ = 116130513865182.

The previous prime is 116130513865109. The next prime is 116130513865237. The reversal of 116130513865183 is 381568315031611.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 116130513865183 - 217 = 116130513734111 is a prime.

It is a super-2 number, since 2×1161305138651832 (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 116130513865183.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (116130513862183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 58065256932591 + 58065256932592.

It is an arithmetic number, because the mean of its divisors is an integer number (58065256932592).

Almost surely, 2116130513865183 is an apocalyptic number.

116130513865183 is a deficient number, since it is larger than the sum of its proper divisors (1).

116130513865183 is an equidigital number, since it uses as much as digits as its factorization.

116130513865183 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1555200, while the sum is 52.

Adding to 116130513865183 its reverse (381568315031611), we get a palindrome (497698828896794).

The spelling of 116130513865183 in words is "one hundred sixteen trillion, one hundred thirty billion, five hundred thirteen million, eight hundred sixty-five thousand, one hundred eighty-three".