Base | Representation |
---|---|
bin | 1010100100000110100100… |
… | …0000100001001110001110 |
3 | 1112010102020221110210122002 |
4 | 2221001221000201032032 |
5 | 3010301220421442032 |
6 | 40412004124352302 |
7 | 2306116166061326 |
oct | 251015100411616 |
9 | 45112227423562 |
10 | 11615353312142 |
11 | 3779053151128 |
12 | 13771723a5692 |
13 | 663427b73238 |
14 | 2c2286930286 |
15 | 15221e37b862 |
hex | a906902138e |
11615353312142 has 4 divisors (see below), whose sum is σ = 17423029968216. Its totient is φ = 5807676656070.
The previous prime is 11615353312141. The next prime is 11615353312159. The reversal of 11615353312142 is 24121335351611.
It is a semiprime because it is the product of two primes.
It is a junction number, because it is equal to n+sod(n) for n = 11615353312096 and 11615353312105.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11615353312141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2903838328034 + ... + 2903838328037.
It is an arithmetic number, because the mean of its divisors is an integer number (4355757492054).
Almost surely, 211615353312142 is an apocalyptic number.
11615353312142 is a deficient number, since it is larger than the sum of its proper divisors (5807676656074).
11615353312142 is an equidigital number, since it uses as much as digits as its factorization.
11615353312142 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5807676656073.
The product of its digits is 64800, while the sum is 38.
Adding to 11615353312142 its reverse (24121335351611), we get a palindrome (35736688663753).
The spelling of 11615353312142 in words is "eleven trillion, six hundred fifteen billion, three hundred fifty-three million, three hundred twelve thousand, one hundred forty-two".
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