Base | Representation |
---|---|
bin | 1010100100000111001110… |
… | …1010010100000100101101 |
3 | 1112010102201101210010211122 |
4 | 2221001303222110010231 |
5 | 3010302102200243433 |
6 | 40412033551230325 |
7 | 2306123466202253 |
oct | 251016352240455 |
9 | 45112641703748 |
10 | 11615532040493 |
11 | 3779135025407 |
12 | 13772022183a5 |
13 | 663455bc0364 |
14 | 2c22a25765d3 |
15 | 15222edd3198 |
hex | a9073a9412d |
11615532040493 has 2 divisors, whose sum is σ = 11615532040494. Its totient is φ = 11615532040492.
The previous prime is 11615532040447. The next prime is 11615532040517. The reversal of 11615532040493 is 39404023551611.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 6002906706889 + 5612625333604 = 2450083^2 + 2369098^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11615532040493 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11615532040403) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5807766020246 + 5807766020247.
It is an arithmetic number, because the mean of its divisors is an integer number (5807766020247).
Almost surely, 211615532040493 is an apocalyptic number.
It is an amenable number.
11615532040493 is a deficient number, since it is larger than the sum of its proper divisors (1).
11615532040493 is an equidigital number, since it uses as much as digits as its factorization.
11615532040493 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 388800, while the sum is 44.
The spelling of 11615532040493 in words is "eleven trillion, six hundred fifteen billion, five hundred thirty-two million, forty thousand, four hundred ninety-three".
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