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11617210455983 = 113396173109709
BaseRepresentation
bin1010100100001101011110…
…1100111101011110101111
31112010121001101000111001022
42221003113230331132233
53010314021334042413
640412512305404355
72306213206406006
oct251032754753657
945117041014038
1011617210455983
113779916495850
1213775b03396bb
13663662850212
142c23c143dc3d
151522cc421608
hexa90d7b3d7af

11617210455983 has 8 divisors (see below), whose sum is σ = 12673361889360. Its totient is φ = 10561065921280.

The previous prime is 11617210455979. The next prime is 11617210456013. The reversal of 11617210455983 is 38955401271611.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11617210455983 - 22 = 11617210455979 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11617210455943) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2180933 + ... + 5290641.

It is an arithmetic number, because the mean of its divisors is an integer number (1584170236170).

It is a 1-persistent number, because it is pandigital, but 2⋅11617210455983 = 23234420911966 is not.

Almost surely, 211617210455983 is an apocalyptic number.

11617210455983 is a deficient number, since it is larger than the sum of its proper divisors (1056151433377).

11617210455983 is a wasteful number, since it uses less digits than its factorization.

11617210455983 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3449337.

The product of its (nonzero) digits is 1814400, while the sum is 53.

The spelling of 11617210455983 in words is "eleven trillion, six hundred seventeen billion, two hundred ten million, four hundred fifty-five thousand, nine hundred eighty-three".

Divisors: 1 11 339617 3109709 3735787 34206799 1056110041453 11617210455983