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116231207 is a prime number
BaseRepresentation
bin1101110110110…
…00110000100111
322002201011020112
412323120300213
5214223344312
615311123235
72610643331
oct673306047
9262634215
10116231207
115a678254
1232b1351b
131b107681
1411618451
15a30dd22
hex6ed8c27

116231207 has 2 divisors, whose sum is σ = 116231208. Its totient is φ = 116231206.

The previous prime is 116231153. The next prime is 116231221. The reversal of 116231207 is 702132611.

It is a strong prime.

It is an emirp because it is prime and its reverse (702132611) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 116231207 - 210 = 116230183 is a prime.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (116231267) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 58115603 + 58115604.

It is an arithmetic number, because the mean of its divisors is an integer number (58115604).

Almost surely, 2116231207 is an apocalyptic number.

116231207 is a deficient number, since it is larger than the sum of its proper divisors (1).

116231207 is an equidigital number, since it uses as much as digits as its factorization.

116231207 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 504, while the sum is 23.

The square root of 116231207 is about 10781.0577866924. The cubic root of 116231207 is about 488.0237029941.

Adding to 116231207 its reverse (702132611), we get a palindrome (818363818).

The spelling of 116231207 in words is "one hundred sixteen million, two hundred thirty-one thousand, two hundred seven".