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1163065004131 is a prime number
BaseRepresentation
bin10000111011001100000…
…100111001000001100011
311010012001222222220201111
4100323030010321001203
5123023424120113011
62250145451244151
7150012556263232
oct20731404710143
94105058886644
101163065004131
11409286968018
121694b0149657
13858a4529574
1440415044b19
15203c2338121
hex10ecc139063

1163065004131 has 2 divisors, whose sum is σ = 1163065004132. Its totient is φ = 1163065004130.

The previous prime is 1163065004119. The next prime is 1163065004183. The reversal of 1163065004131 is 1314005603611.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1163065004131 - 215 = 1163064971363 is a prime.

It is a super-2 number, since 2×11630650041312 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1163065004093 and 1163065004102.

It is not a weakly prime, because it can be changed into another prime (1163065005131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 581532502065 + 581532502066.

It is an arithmetic number, because the mean of its divisors is an integer number (581532502066).

Almost surely, 21163065004131 is an apocalyptic number.

1163065004131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1163065004131 is an equidigital number, since it uses as much as digits as its factorization.

1163065004131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6480, while the sum is 31.

The spelling of 1163065004131 in words is "one trillion, one hundred sixty-three billion, sixty-five million, four thousand, one hundred thirty-one".