Base | Representation |
---|---|
bin | 1010100101000010101111… |
… | …0110111011001111110011 |
3 | 1112011221221201222012010102 |
4 | 2221100223312323033303 |
5 | 3011032311324200212 |
6 | 40423235103423015 |
7 | 2310230410246421 |
oct | 251205366731763 |
9 | 45157851865112 |
10 | 11631507256307 |
11 | 3784992682504 |
12 | 137a3202b4a6b |
13 | 664b007a9693 |
14 | 2c2d7a0d6111 |
15 | 1528676305c2 |
hex | a942bdbb3f3 |
11631507256307 has 2 divisors, whose sum is σ = 11631507256308. Its totient is φ = 11631507256306.
The previous prime is 11631507256301. The next prime is 11631507256333. The reversal of 11631507256307 is 70365270513611.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11631507256307 - 210 = 11631507255283 is a prime.
It is a super-2 number, since 2×116315072563072 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11631507256301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5815753628153 + 5815753628154.
It is an arithmetic number, because the mean of its divisors is an integer number (5815753628154).
Almost surely, 211631507256307 is an apocalyptic number.
11631507256307 is a deficient number, since it is larger than the sum of its proper divisors (1).
11631507256307 is an equidigital number, since it uses as much as digits as its factorization.
11631507256307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 793800, while the sum is 47.
Adding to 11631507256307 its reverse (70365270513611), we get a palindrome (81996777769918).
The spelling of 11631507256307 in words is "eleven trillion, six hundred thirty-one billion, five hundred seven million, two hundred fifty-six thousand, three hundred seven".
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