Base | Representation |
---|---|
bin | 1010100101000110111101… |
… | …0000010111111101010111 |
3 | 1112012001212112122222012212 |
4 | 2221101233100113331113 |
5 | 3011042120312012413 |
6 | 40423543215304035 |
7 | 2310300420362216 |
oct | 251215720277527 |
9 | 45161775588185 |
10 | 11632638000983 |
11 | 378541298673a |
12 | 137a596b1b01b |
13 | 664c50b3327c |
14 | 2c304635907d |
15 | 1528d1a3aca8 |
hex | a946f417f57 |
11632638000983 has 2 divisors, whose sum is σ = 11632638000984. Its totient is φ = 11632638000982.
The previous prime is 11632638000941. The next prime is 11632638001207. The reversal of 11632638000983 is 38900083623611.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11632638000983 - 224 = 11632621223767 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11632638000913) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5816319000491 + 5816319000492.
It is an arithmetic number, because the mean of its divisors is an integer number (5816319000492).
Almost surely, 211632638000983 is an apocalyptic number.
11632638000983 is a deficient number, since it is larger than the sum of its proper divisors (1).
11632638000983 is an equidigital number, since it uses as much as digits as its factorization.
11632638000983 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1119744, while the sum is 50.
The spelling of 11632638000983 in words is "eleven trillion, six hundred thirty-two billion, six hundred thirty-eight million, nine hundred eighty-three", and thus it is an aban number.
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