Base | Representation |
---|---|
bin | 10101101011011110… |
… | …01011111111110001 |
3 | 1010001010210110211022 |
4 | 22311233023333301 |
5 | 142314034334333 |
6 | 5202531425225 |
7 | 561265463012 |
oct | 126557137761 |
9 | 33033713738 |
10 | 11638980593 |
11 | 4a329a0429 |
12 | 2309a55215 |
13 | 1136420a86 |
14 | 7c5ac3009 |
15 | 481c0bc98 |
hex | 2b5bcbff1 |
11638980593 has 2 divisors, whose sum is σ = 11638980594. Its totient is φ = 11638980592.
The previous prime is 11638980583. The next prime is 11638980599. The reversal of 11638980593 is 39508983611.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11607261169 + 31719424 = 107737^2 + 5632^2 .
It is an emirp because it is prime and its reverse (39508983611) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11638980593 is a prime.
It is not a weakly prime, because it can be changed into another prime (11638980599) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5819490296 + 5819490297.
It is an arithmetic number, because the mean of its divisors is an integer number (5819490297).
Almost surely, 211638980593 is an apocalyptic number.
It is an amenable number.
11638980593 is a deficient number, since it is larger than the sum of its proper divisors (1).
11638980593 is an equidigital number, since it uses as much as digits as its factorization.
11638980593 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1399680, while the sum is 53.
The spelling of 11638980593 in words is "eleven billion, six hundred thirty-eight million, nine hundred eighty thousand, five hundred ninety-three".
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