Base | Representation |
---|---|
bin | 11010011110101010010011… |
… | …110101010111001101000011 |
3 | 120021100002212110002121000102 |
4 | 122132222103311113031003 |
5 | 110231004321204100141 |
6 | 1051403130035513015 |
7 | 33346453532026646 |
oct | 3236522365271503 |
9 | 507302773077012 |
10 | 116456223503171 |
11 | 34119897184042 |
12 | 11089bb575876b |
13 | 4cc9a0c1a1156 |
14 | 20a8722db1a5d |
15 | d6e460ebe99b |
hex | 69ea93d57343 |
116456223503171 has 2 divisors, whose sum is σ = 116456223503172. Its totient is φ = 116456223503170.
The previous prime is 116456223503149. The next prime is 116456223503299. The reversal of 116456223503171 is 171305322654611.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-116456223503171 is a prime.
It is a super-3 number, since 3×1164562235031713 (a number of 43 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (116456223503101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 58228111751585 + 58228111751586.
It is an arithmetic number, because the mean of its divisors is an integer number (58228111751586).
Almost surely, 2116456223503171 is an apocalyptic number.
116456223503171 is a deficient number, since it is larger than the sum of its proper divisors (1).
116456223503171 is an equidigital number, since it uses as much as digits as its factorization.
116456223503171 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 907200, while the sum is 47.
The spelling of 116456223503171 in words is "one hundred sixteen trillion, four hundred fifty-six billion, two hundred twenty-three million, five hundred three thousand, one hundred seventy-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •