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116571701 is a prime number
BaseRepresentation
bin1101111001010…
…11111000110101
322010100110022102
412330223320311
5214320243301
615322311445
72613562121
oct674537065
9263313272
10116571701
115a890054
1233058585
131b1c664c
14116a6581
15a379b6b
hex6f2be35

116571701 has 2 divisors, whose sum is σ = 116571702. Its totient is φ = 116571700.

The previous prime is 116571673. The next prime is 116571727. The reversal of 116571701 is 107175611.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 87422500 + 29149201 = 9350^2 + 5399^2 .

It is an emirp because it is prime and its reverse (107175611) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 116571701 - 226 = 49462837 is a prime.

It is a super-2 number, since 2×1165717012 = 27177922948066802, which contains 22 as substring.

It is equal to p6657410 and since 116571701 and 6657410 have the same sum of digits, it is a Honaker prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (116571731) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 58285850 + 58285851.

It is an arithmetic number, because the mean of its divisors is an integer number (58285851).

Almost surely, 2116571701 is an apocalyptic number.

It is an amenable number.

116571701 is a deficient number, since it is larger than the sum of its proper divisors (1).

116571701 is an equidigital number, since it uses as much as digits as its factorization.

116571701 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1470, while the sum is 29.

The square root of 116571701 is about 10796.8375462447. The cubic root of 116571701 is about 488.4997861073.

The spelling of 116571701 in words is "one hundred sixteen million, five hundred seventy-one thousand, seven hundred one".