Base | Representation |
---|---|
bin | 1010100110111000100001… |
… | …1010110100100000010111 |
3 | 1112021222120020012222110212 |
4 | 2221232020122310200113 |
5 | 3012042034441101243 |
6 | 40445544324240035 |
7 | 2312430052161566 |
oct | 251561032644027 |
9 | 45258506188425 |
10 | 11663124940823 |
11 | 3797337a76894 |
12 | 1384484b4001b |
13 | 667a9c059a45 |
14 | 2c46d9319bdd |
15 | 1535b829d318 |
hex | a9b886b4817 |
11663124940823 has 2 divisors, whose sum is σ = 11663124940824. Its totient is φ = 11663124940822.
The previous prime is 11663124940799. The next prime is 11663124940853. The reversal of 11663124940823 is 32804942136611.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11663124940823 - 216 = 11663124875287 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11663124940853) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5831562470411 + 5831562470412.
It is an arithmetic number, because the mean of its divisors is an integer number (5831562470412).
Almost surely, 211663124940823 is an apocalyptic number.
11663124940823 is a deficient number, since it is larger than the sum of its proper divisors (1).
11663124940823 is an equidigital number, since it uses as much as digits as its factorization.
11663124940823 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1492992, while the sum is 50.
The spelling of 11663124940823 in words is "eleven trillion, six hundred sixty-three billion, one hundred twenty-four million, nine hundred forty thousand, eight hundred twenty-three".
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