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116665522153 is a prime number
BaseRepresentation
bin110110010100111001…
…1101001011111101001
3102011010121202120210221
41230221303221133221
53402412333202103
6125332335010041
711300036401435
oct1545163513751
9364117676727
10116665522153
1145528711604
121a73b069921
13b003422b5b
14590a5539c5
15307c3921bd
hex1b29ce97e9

116665522153 has 2 divisors, whose sum is σ = 116665522154. Its totient is φ = 116665522152.

The previous prime is 116665522093. The next prime is 116665522157. The reversal of 116665522153 is 351225566611.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 85853688064 + 30811834089 = 293008^2 + 175533^2 .

It is a cyclic number.

It is not a de Polignac number, because 116665522153 - 217 = 116665391081 is a prime.

It is a super-3 number, since 3×1166655221533 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (116665522157) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 58332761076 + 58332761077.

It is an arithmetic number, because the mean of its divisors is an integer number (58332761077).

Almost surely, 2116665522153 is an apocalyptic number.

It is an amenable number.

116665522153 is a deficient number, since it is larger than the sum of its proper divisors (1).

116665522153 is an equidigital number, since it uses as much as digits as its factorization.

116665522153 is an evil number, because the sum of its binary digits is even.

The product of its digits is 324000, while the sum is 43.

The spelling of 116665522153 in words is "one hundred sixteen billion, six hundred sixty-five million, five hundred twenty-two thousand, one hundred fifty-three".