1168432957440 has 1728 divisors, whose sum is σ = 5033390544000. Its totient is φ = 259852271616.

The previous prime is 1168432957427. The next prime is 1168432957441. The reversal of 1168432957440 is 447592348611.

1168432957440 is a `hidden beast` number, since 1 + 1 + 6 + 8 + 4 + 3 + 29 + 574 + 40 = 666.

It is a tau number, because it is divible by the number of its divisors (1728).

It is a Harshad number since it is a multiple of its sum of digits (54).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1168432957441) by changing a digit.

It is a polite number, since it can be written in 143 ways as a sum of consecutive naturals, for example, 31579269102 + ... + 31579269138.

It is an arithmetic number, because the mean of its divisors is an integer number (2912841750).

It is a 1-persistent number, because it is pandigital, but 2⋅1168432957440 = 2336865914880 is not.

Almost surely, 2^{1168432957440} is an apocalyptic number.

1168432957440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1168432957440, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2516695272000).

1168432957440 is an abundant number, since it is smaller than the sum of its proper divisors (3864957586560).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1168432957440 is an frugal number, since it uses more digits than its factorization.

1168432957440 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 137 (or 54 counting only the distinct ones).

The product of its (nonzero) digits is 5806080, while the sum is 54.

The spelling of 1168432957440 in words is "one trillion, one hundred sixty-eight billion, four hundred thirty-two million, nine hundred fifty-seven thousand, four hundred forty".