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117064852691 is a prime number
BaseRepresentation
bin110110100000110011…
…0111110010011010011
3102012011110011200022212
41231001212332103103
53404222100241231
6125440122022335
711312655554423
oct1550146762323
9365143150285
10117064852691
114571306a546
121a8309479ab
13b06808b807
1459475c2483
1530a247242b
hex1b419be4d3

117064852691 has 2 divisors, whose sum is σ = 117064852692. Its totient is φ = 117064852690.

The previous prime is 117064852649. The next prime is 117064852693. The reversal of 117064852691 is 196258460711.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 117064852691 - 218 = 117064590547 is a prime.

It is a super-3 number, since 3×1170648526913 (a number of 34 digits) contains 333 as substring.

Together with 117064852693, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (117064852693) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 58532426345 + 58532426346.

It is an arithmetic number, because the mean of its divisors is an integer number (58532426346).

Almost surely, 2117064852691 is an apocalyptic number.

117064852691 is a deficient number, since it is larger than the sum of its proper divisors (1).

117064852691 is an equidigital number, since it uses as much as digits as its factorization.

117064852691 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 725760, while the sum is 50.

The spelling of 117064852691 in words is "one hundred seventeen billion, sixty-four million, eight hundred fifty-two thousand, six hundred ninety-one".