11710470000017 has 2 divisors, whose sum is σ = 11710470000018. Its totient is φ = 11710470000016.

The previous prime is 11710469999989. The next prime is 11710470000071. The reversal of 11710470000017 is 71000007401711.

It is a happy number.

11710470000017 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

Together with next prime (11710470000071) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10851022339921 + 859447660096 = 3294089^2 + 927064^2 .

It is an emirp because it is prime and its reverse (71000007401711) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11710470000017 - 2¹⁸ = 11710469737873 is a prime.

It is not a weakly prime, because it can be changed into another prime (11710470300017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5855235000008 + 5855235000009.

It is an arithmetic number, because the mean of its divisors is an integer number (5855235000009).

Almost surely, 2^{11710470000017} is an apocalyptic number.

It is an amenable number.

11710470000017 is a deficient number, since it is larger than the sum of its proper divisors (1).

11710470000017 is an equidigital number, since it uses as much as digits as its factorization.

11710470000017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1372, while the sum is 29.

Adding to 11710470000017 its reverse (71000007401711), we get a palindrome (82710477401728).

The spelling of 11710470000017 in words is "eleven trillion, seven hundred ten billion, four hundred seventy million, seventeen", and thus it is an aban number.