Base | Representation |
---|---|
bin | 1010101001110011000011… |
… | …1110000110000001101111 |
3 | 1112110202210212101110122102 |
4 | 2222130300332012001233 |
5 | 3013402112013301200 |
6 | 40524545115005315 |
7 | 2316151644103235 |
oct | 252346076060157 |
9 | 45422725343572 |
10 | 11713197400175 |
11 | 38065a262a6a7 |
12 | 139211a13983b |
13 | 66c71bb1980b |
14 | 2c6cc950c955 |
15 | 154a491a76d5 |
hex | aa730f8606f |
11713197400175 has 48 divisors (see below), whose sum is σ = 15876647829504. Its totient is φ = 8533874880000.
The previous prime is 11713197400123. The next prime is 11713197400273. The reversal of 11713197400175 is 57100479131711.
11713197400175 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 11713197400175 - 218 = 11713197138031 is a prime.
It is a super-3 number, since 3×117131974001753 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 126842270 + ... + 126934580.
It is an arithmetic number, because the mean of its divisors is an integer number (330763496448).
Almost surely, 211713197400175 is an apocalyptic number.
11713197400175 is a deficient number, since it is larger than the sum of its proper divisors (4163450429329).
11713197400175 is a wasteful number, since it uses less digits than its factorization.
11713197400175 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 102000 (or 101995 counting only the distinct ones).
The product of its (nonzero) digits is 185220, while the sum is 47.
The spelling of 11713197400175 in words is "eleven trillion, seven hundred thirteen billion, one hundred ninety-seven million, four hundred thousand, one hundred seventy-five".
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