Base | Representation |
---|---|
bin | 11010101000100010011101… |
… | …001101101110000011011011 |
3 | 120100201222212112221121121202 |
4 | 122220202131031232003123 |
5 | 110323114422320402211 |
6 | 1053043023005424415 |
7 | 33446503066450301 |
oct | 3250423515560333 |
9 | 510658775847552 |
10 | 117134985715931 |
11 | 34360739808857 |
12 | 1117966586b10b |
13 | 5048a2169b681 |
14 | 20cd513866271 |
15 | d81e3a80953b |
hex | 6a889d36e0db |
117134985715931 has 2 divisors, whose sum is σ = 117134985715932. Its totient is φ = 117134985715930.
The previous prime is 117134985715903. The next prime is 117134985715963. The reversal of 117134985715931 is 139517589431711.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 117134985715931 - 234 = 117117805846747 is a prime.
It is a super-2 number, since 2×1171349857159312 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (117134985718931) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 58567492857965 + 58567492857966.
It is an arithmetic number, because the mean of its divisors is an integer number (58567492857966).
Almost surely, 2117134985715931 is an apocalyptic number.
117134985715931 is a deficient number, since it is larger than the sum of its proper divisors (1).
117134985715931 is an equidigital number, since it uses as much as digits as its factorization.
117134985715931 is an evil number, because the sum of its binary digits is even.
The product of its digits is 28576800, while the sum is 65.
The spelling of 117134985715931 in words is "one hundred seventeen trillion, one hundred thirty-four billion, nine hundred eighty-five million, seven hundred fifteen thousand, nine hundred thirty-one".
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