Base | Representation |
---|---|
bin | 11010101000100010011101… |
… | …001101101110000010111111 |
3 | 120100201222212112221121120201 |
4 | 122220202131031232002333 |
5 | 110323114422320402103 |
6 | 1053043023005424331 |
7 | 33446503066450231 |
oct | 3250423515560277 |
9 | 510658775847521 |
10 | 117134985715903 |
11 | 34360739808831 |
12 | 1117966586b0a7 |
13 | 5048a2169b65c |
14 | 20cd513866251 |
15 | d81e3a80951d |
hex | 6a889d36e0bf |
117134985715903 has 2 divisors, whose sum is σ = 117134985715904. Its totient is φ = 117134985715902.
The previous prime is 117134985715897. The next prime is 117134985715931. The reversal of 117134985715903 is 309517589431711.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 117134985715903 - 213 = 117134985707711 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (117134985715963) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 58567492857951 + 58567492857952.
It is an arithmetic number, because the mean of its divisors is an integer number (58567492857952).
Almost surely, 2117134985715903 is an apocalyptic number.
117134985715903 is a deficient number, since it is larger than the sum of its proper divisors (1).
117134985715903 is an equidigital number, since it uses as much as digits as its factorization.
117134985715903 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 28576800, while the sum is 64.
The spelling of 117134985715903 in words is "one hundred seventeen trillion, one hundred thirty-four billion, nine hundred eighty-five million, seven hundred fifteen thousand, nine hundred three".
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