Base | Representation |
---|---|
bin | 11010101000101100000000… |
… | …111110110001111111100011 |
3 | 120100202222100211222122020111 |
4 | 122220230000332301333203 |
5 | 110323301432330043344 |
6 | 1053051441253152151 |
7 | 33450315326012104 |
oct | 3250540076617743 |
9 | 510688324878214 |
10 | 117145249456099 |
11 | 34365026390747 |
12 | 1117b64b02b657 |
13 | 5049998bcc5c7 |
14 | 20cdc08a403ab |
15 | d8233b912834 |
hex | 6a8b00fb1fe3 |
117145249456099 has 2 divisors, whose sum is σ = 117145249456100. Its totient is φ = 117145249456098.
The previous prime is 117145249456097. The next prime is 117145249456223. The reversal of 117145249456099 is 990654942541711.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 117145249456099 - 21 = 117145249456097 is a prime.
Together with 117145249456097, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (117145249456097) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 58572624728049 + 58572624728050.
It is an arithmetic number, because the mean of its divisors is an integer number (58572624728050).
Almost surely, 2117145249456099 is an apocalyptic number.
117145249456099 is a deficient number, since it is larger than the sum of its proper divisors (1).
117145249456099 is an equidigital number, since it uses as much as digits as its factorization.
117145249456099 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 97977600, while the sum is 67.
The spelling of 117145249456099 in words is "one hundred seventeen trillion, one hundred forty-five billion, two hundred forty-nine million, four hundred fifty-six thousand, ninety-nine".
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