Base | Representation |
---|---|
bin | 110110100011010011… |
… | …0001010010011001011 |
3 | 102012101021121201012211 |
4 | 1231012212022103023 |
5 | 3404410010311041 |
6 | 125452311245551 |
7 | 11315023016314 |
oct | 1550646122313 |
9 | 365337551184 |
10 | 117148525771 |
11 | 4575631a352 |
12 | 1a8549798b7 |
13 | b07c506a04 |
14 | 595476360b |
15 | 30a999e481 |
hex | 1b4698a4cb |
117148525771 has 2 divisors, whose sum is σ = 117148525772. Its totient is φ = 117148525770.
The previous prime is 117148525759. The next prime is 117148525783. The reversal of 117148525771 is 177525841711.
It is a balanced prime because it is at equal distance from previous prime (117148525759) and next prime (117148525783).
It is a cyclic number.
It is not a de Polignac number, because 117148525771 - 27 = 117148525643 is a prime.
It is a super-2 number, since 2×1171485257712 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (117148525471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 58574262885 + 58574262886.
It is an arithmetic number, because the mean of its divisors is an integer number (58574262886).
Almost surely, 2117148525771 is an apocalyptic number.
117148525771 is a deficient number, since it is larger than the sum of its proper divisors (1).
117148525771 is an equidigital number, since it uses as much as digits as its factorization.
117148525771 is an evil number, because the sum of its binary digits is even.
The product of its digits is 548800, while the sum is 49.
The spelling of 117148525771 in words is "one hundred seventeen billion, one hundred forty-eight million, five hundred twenty-five thousand, seven hundred seventy-one".
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